[Maxima-discuss] Equation system with trigonometric function

[Stefano Milani]

Dear all,

I would like to solve this system of equation:

(T) Ky*x3+T0
(phi) Kx*x2+u
(eq1) (-sin(Kx*x2+u-%pi/4)*(-Ky*x3-T0)-bx*x2)/M=0
(eq2) (cos(Kx*x2+u-%pi/4)*(Ky*x3+T0)-by*x3-M*g)/M=0
(eq3) (cos(Kx*x2+u-%pi/4)*(Ky*x3+T0)-by*x3-M*g)/M=0


Where the required term are x2,x3,u
Which command can I use to obtain all solutions?

Best regards


Stefano Milani




---
Questa e-mail Ú stata controllata per individuare virus con Avast antivirus.
https://www.avast.com/antivirus

[Stavros Macrakis (Σταῦρος Μακράκης)]

Not sure I understand your problem.

Do you mean that Ky*x3+T0=0 and Kx*x2+u=0?

What is the purpose of the denominator (/M) in eqN? After all, X/M = 0 is
equivalent to X=0 for all M, except M=0, which is invalid.

eq2 is identical to eq3, so eq3 is redundant.

Please clarify.

-s

Post by Stefano Milani
Dear all,
(T) Ky*x3+T0
(phi) Kx*x2+u
(eq1) (-sin(Kx*x2+u-%pi/4)*(-Ky*x3-T0)-bx*x2)/M=0
(eq2) (cos(Kx*x2+u-%pi/4)*(Ky*x3+T0)-by*x3-M*g)/M=0
(eq3) (cos(Kx*x2+u-%pi/4)*(Ky*x3+T0)-by*x3-M*g)/M=0
Where the required term are x2,x3,u
Which command can I use to obtain *all* solutions?
Best regards
Stefano Milani
<https://www.avast.com/sig-email?utm_medium=email&utm_source=link&utm_campaign=sig-email&utm_content=emailclient> Mail
priva di virus. www.avast.com
<https://www.avast.com/sig-email?utm_medium=email&utm_source=link&utm_campaign=sig-email&utm_content=emailclient>
<#m_7861398920438109585_DAB4FAD8-2DD7-40BB-A1B8-4E2AA1F9FDF2>
------------------------------------------------------------
------------------
Check out the vibrant tech community on one of the world's most
engaging tech sites, Slashdot.org! http://sdm.link/slashdot
_______________________________________________
Maxima-discuss mailing list
https://lists.sourceforge.net/lists/listinfo/maxima-discuss

[Stefano Milani]

I’m sorry,

eq3 is the following:

(eq3) (l*sin(Kx*x2+u)*(Ky*x3+T0))=0

M is a mass, so is positive define (and in the equation is not necessary).
The first two equation (T and phi) are not equation but variable definition used in three following system of three equations.

T = T0+Ky*x3;
phi= Kx*x2+u;

Hope to clarify.

Best regards

Stefano Milani


Da: Stavros Macrakis (ΣταῊρος Μακράκης)
Inviato: lunedì 24 luglio 2017 21:43
A: Stefano Milani
Cc: maxima-***@lists.sourceforge.net
Oggetto: Re: [Maxima-discuss] Equation system with trigonometric function

Not sure I understand your problem.

Do you mean that Ky*x3+T0=0 and Kx*x2+u=0?

What is the purpose of the denominator (/M) in eqN?  After all, X/M = 0 is equivalent to X=0 for all M, except M=0, which is invalid.

eq2 is identical to eq3, so eq3 is redundant.

Please clarify.

         -s

On Mon, Jul 24, 2017 at 3:15 PM, Stefano Milani <***@enerconsulting.it> wrote:
Dear all,
 
I would like to solve this system of equation:
 
(T)          Ky*x3+T0
(phi)      Kx*x2+u
(eq1)     (-sin(Kx*x2+u-%pi/4)*(-Ky*x3-T0)-bx*x2)/M=0
(eq2)     (cos(Kx*x2+u-%pi/4)*(Ky*x3+T0)-by*x3-M*g)/M=0
(eq3)     (cos(Kx*x2+u-%pi/4)*(Ky*x3+T0)-by*x3-M*g)/M=0
 
 
Where the required term are x2,x3,u
Which command can I use to obtain all solutions?
 
Best regards
 
 
Stefano Milani
 


Mail priva di virus. www.avast.com
------------------------------------------------------------------------------
Check out the vibrant tech community on one of the world's most
engaging tech sites, Slashdot.org! http://sdm.link/slashdot
_______________________________________________
Maxima-discuss mailing list
Maxima-***@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/maxima-discuss




---
Questa e-mail Ú stata controllata per individuare virus con Avast antivirus.
https://www.avast.com/antivirus